HELP Quadrilateral ABCD has coordinates A(-2, 0), B(0,4), C(4, 6), and D(2, 2). What are the coordinates of the image Rx-axis (ABCD) = A'B'C'D'?
A=(
B'=(
C=(
D'=(

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

happy to

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p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder