To the nearest unit, what is the perimeter of this pentagon? 5
4
3
2
1
65
-3 -2 -1
2 3
4
بي ط ا
27 units
29 units
30 units
34 units

The perimeter of the pentagon is;

29 units

Step-by-step explanation:

Let A, B, C, D, and E represent the vertices of the pentagon

The "x" and "y" coordinates of the vertices of the pentagon are given as follows;

A(-6, 2), B(-2, -2), C(5, -2), D(5, 2), E(-2, 5)

The length of the sides between each pair of coordinates can be found using the following formula;

Therefore, we have;

Length of segment AB = √((-2 - (2))² + (-2 - (-6))²) = 4·√2

Length of segment BC = √((-2 - (-2))² + (5 - (-2))²) = 7

Length of segment CD = √((5 - 5)² + (2 - (-2))²) = 4

Length of segment DE = √((5 - 2)² + (-2 - 5)²) = √58

Length of segment EA = √((5 - (2))² + (-2 - (-6))²) = 5

The length of the perimeter of the pentagon = 5+√58 + 4 + 7 + 4·√2 ≈ 29.2726273554 ≈ 29

The length of the perimeter of the pentagon ≈ 29.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!