Solve the following proportion for u/6 = 8/11. Round your answer to the nearest tenth.

7/10

Step-by-step explanation:First, we convert the fraction to a decimal number by dividing the numerator by the denominator:

8 / 11 = 0.72

There are two parts to the decimal number above:

Integer Part: 0

Fractional Part: 72

Now, we will make the Fractional Part just one digit (nearest tenth) by using our rounding rules.*

In this case, Rule I applies, so 8/11 (or 0.72) rounded to the nearest tenth in decimal format is:

0.7

Next, we will make 8/11 rounded to the nearest tenth in fraction format. Since you can divide our decimal format answer above by 1 and keep the same value, you can make it like this:

0.7 = 0.7/1

Then, we multiply the numerator and denominator by 10 to get rid of the decimal point:

(0.7 x 10) / (1 x 10) = 7/10

That's it. 8/11 rounded to the nearest tenth is displayed below (simplified if necessary):

7/10

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.