The length of a rectangle is 5 in. more than the four times the width. The perimeter of the rectangle is 80 in. Find the length and width.

L=33 and W=7

Step one, What do we know?

We are told that the perimeter is  80  feet; since the perimeter of a rectangle is 2 times the length plus the width. We are also told that the length is 5 feet longer than four times the width.

Step two, Start solving it.

Combining these two we have 4w + 5=40 - w. We put the w on the right side and the 5 on the left side by adding and subtracting. Now we have 5w=35. We divide both sides by 5 and we get W=7. In order to figure out L, we do

40 - W. We get L=33.

the answer for this question is 38

i think is g(1)=-1.

hope that i can