What is an equation of the line that is perpendicular to y-4=2(×-6) and passes thru the point (-3,-5)

An equation of the line that is perpendicular to y-4=2(x-6) and passes thru the point (-3,-5) will be:

Step-by-step explanation:

We know the point-slope form of the line equation is

where

Given the line

y-4 = 2(x-6)

comparing with the point-slope form of the line equation

The slope = m = 2

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

slope = m = 2

so, the slope of the line perpendicular to y-4 = 2(x-6) will be:

– 1/m = -1/2 = -1/2

substituting the values of the slope = -1/2 and the point (-3, -5)

Subtract 5 from both sides

Simplify

Therefore, an equation of the line that is perpendicular to y-4=2(x-6) and passes thru the point (-3,-5) will be:

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.