Can someone please help with #16

16.

a. Intercepts are where the graph of something meet either the x or y axes. Another way to think of them is as points where either (or both) coordinates are 0. The x-intercept has a y value of 0, and the y-intercept has an x value of 0.

Let's find the y-intercept first, because that's easier. You don't actually need to do any work at all. Theequation they gave you is in slope-intercept form. The formula is y=mx+b, where m is the slope and b is the y-intercept. If you rewrite the equation as y = -60x + 8063, it's easy to tell that 8063 is the y-intercept. But you can calculate it as well. Plug 0 in for x and solve for y.

y=8063-60(0)

 =8063-0

 =8063

This is the number of TEUs on the ship before they start unloading, because x is the number of hours they've been working. At 0 hours, it's impossible for them to have made any progress.

As for the x-intercept, you need to solve for when y=0.

0=8063-60x

60x=8063

x=8063/60

As for graphing, I think you can figure that out yourself. Plot the intercepts, or any 2-3 points (making a table helps), and connect them. Make sure to remember the domain: neither x or y can be negative, because there can't be a negative amount of TEUs or hours.

Hope I could help!

5050 i think

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west