PLS HURRY ALL MATH PEOPLE (05.03 MC)
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 2−x+1 intersect are the solutions of the equation 4−x = 2−x+1. (4 points)

Part B: Make tables to find the solution to 4−x = 2−x+1. Take the integer values of x between −2 and 2. (4 points)

Part C: How can you solve the equation 4−x = 2−x+1 graphically? (2 points)

(10 points)

A: You have 2 equations for y. They will intersect at some point where  "y" is the same for both equations. That is why in equation y=2x+2 you exchange "y" with other equation you got which is y=4x. once you do that you will have

4x=2x+2.  

B: 4x = 2x + 2

  x = -3         -12 = -4   false

  x = -2           -8 = -2   false

  x = -1           -4 = 0    false

  x = 0             0 = 2    false

  x = 1             4 = 4     true

  x = 2             8 = 6     false

  x = 3             12 = 8   false

C. To solve that equation graphically first you draw function y=4x than you draw function y = 2x + 2. After you do that there will be 1 point on graph where functions will intersect. On graph you simply read x value of point where they intersect and that is your solution.

Step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

b

step-by-step explanation: