Find the difference.

(4−5y)−2(3.5y−8)

-12y + 20

Step-by-step explanation:

First, you simplify each term:

apply the distributive property:

4 - 5y - 2 (3.5y) - 2 x -8

Multiply 3.5 by -2:

4 - 5y - 2 (3.5y) - 2 x -8

Multiply -2 by -8:

4 - 5y - 7y +16

Next, we simplify by adding terms:

Add 4 + 16:

-5y - 7y + 20

Subtract 7y from 5y:

-12y + 20

Hence the simplified form is -12y + 20

-4·(3y-5)

Step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.