10 snails is to be chosen from this population. Find the probability that the percentage of streaked-shelled snails in the sample will be (a) 50%. (b) 60%. (c) 70%.

Here is the full question:

(a) 0.2007

(b) 0.2510

(c) 0.2150

Step-by-step explanation:

Given that:

The sample size = 10

Sample proportion= 60% 0.6

Let X represents the no of streaked-shell snails.

The Probability mass function (X) is:

The Binomial probability with mean μ = np

= 10 * 0.6

= 6

Standard deviation σ =

=

= 1.55

The probability that the percentage of the streaked-shelled snails in the sample will be:

a)

= 0.2007

b)

= 0.2510

c)

= 0.2150

10000000000000000000000000000000

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.