The perimeter of a triangle is 21. The smallest side is 3. The 2nd side is twice the smallest side. The 3rd side is 6 more than the 2nd side. Write an equation to solve for the perimeter. Then find the and . Fill in the blanks.

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Step-by-step explanation:

From the question, we are informed that the smallest side is 3 and that the 2nd side is twice the smallest side. This means that the second side will be:

= 3 × 2 = 6

The 3rd side is 6 more than the 2nd side. The 3rd side will be:

= 6 + 6 = 12

The perimeter of a triangle is the addition of its sides. Therefore, the perimeter is:

= 3 + 6 + 12

= 21

The sides are:

1st side = 3

2nd side = 6

3rd side = 12.

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

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