4 A roulette wheel consists of 18 red slots, 18 black slots, and 2 green slots. A player can wager $1 that a marble
will land in a red slot, in which case the player would gain a $1. If the marble lands in a slot that isn't red, then
the player loses their $1 wager. Let X represent the player's gain from a random $1 wager on red. Here's the
probability distribution of X along with summary statistics:
A piz
size
Xro
prot
Lose
Win
-1
1
X = gain ($)
P(X)
20/38
X
18/38
px - $0.05
Mean:
P
Standard deviation:
Ox $1.00
Suppose a player decides to wager $5 instead of $1, so the possible outcomes become either losing or winning
$5. Let Z represent the player's gain from a random $5 wager on red.
The
What are the mean and standard deviation of Z?
any
prot
on a
μ28
dollars
Wha
dollars
Uy

-0.25 and 5

Step-by-step explanation:

Khan

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

the answer is 54 sq. ft. i just did this question, on odyssey ware, and it was right. make brainliest.