What is the answer to this ⅓(6x-9)

9-9x = 0                x=1

Step-by-step explanation:

Put each term in 6+(-9-6 x)/3-x over the common denominator 3: 6+(-9-6 x)/3-x  =  18/3+(-9-6 x)/3-(3 x)/3:

18/3+(-9-6 x)/3-(3 x)/3 = 0

18/3+(-9-6 x)/3-(3 x)/3 = (-3 x+(-9-6 x)+18)/3:

(-3 x-6 x-9+18)/3 = 0

Grouping like terms, -3 x-6 x-9+18 = (18-9)+(-6 x-3 x):

((18-9)+(-6 x-3 x))/3 = 0

-6 x-3 x = -9 x:

(-9 x+(18-9))/3 = 0

18-9 = 9:

(9-9 x)/3 = 0

Multiply both sides of (9-9 x)/3 = 0 by 3:

(3 (9-9 x))/3 = 3×0

(3 (9-9 x))/3 = 3/3×(9-9 x) = 9-9 x:

9-9 x = 3×0

0×3 = 0:

translate k to n and reflect across the line containing jk.