Write an equation of the line that passes through (5, −1) and is perpendicular to the line y=12x−1.

Step-by-step explanation:

solution

let,A(5,-1)

given

y=12x-1

or, y = 12 × x + (-1)

comparing it with y=mx+c

we get

x=1

y = c = -1

now

A(5,-1) and B(1,-1)

equation of line is,

(y-y1)/(x-x1) = (y2-y1)/(x2-x1)

or, (y+1)/(x-5) = (-1+1)/(1-5)

or, (y+1)/(x-5) = 0/-4

cross multiply

-4y-4 = 0

or, 0=4y+4

or, 4y+4=0 is the required eqn

I think this is the process and answer too.

I hope this helps you

answer:

c. the third graph