Need help ASAP!! Sharon is 5 times as old as her daughter. 4 years ago, the square of the sum of their ages is equal to 256. Forming an algebraic equation, find their present ages.

Sharon is 36

Her daughter is 7 years and 2 months

Step-by-step explanation:

sharon is 5× as old

her daughter is written as 1 (because we dont know about her age)

then square root of 256 to find square which is equal as said in the queston:which is 16

algebraic equation would be:5n+16 (n represents the years and 5 is how many times older sharon is and 16 is how old their square sum of agewas 4 years ago)

Their present age would be:

Sharon=5x4+16=36

Daughter =36÷5=7 years 2 months

an altitude of 15,000 feet

step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!