1)Identify the conjugate for 6 – 7√3 and explain your reasoning. 2)Multiply the radical expression 6 – 7√3 and its conjugate and write in simplified form. Show all your steps
3) Explain why we always get an integer when multiplying a radical expression by its conjugate? Provide your own appropriate example with supporting work that matches your explanation..

1) The conjugate for is .

2) -111

3) It is because number and its conjugate have the same numbers but their second components are opposite to each other.

Step-by-step explanation:

1) A radical number of the form , , where the first component is a non-radical real number which acts as a "pivot" and the second component is the radical component, which generates a "displacement" from pivot.

The conjugate of is a real number ,  , which that is "pivot" plus "displacement" in the direction opposite to that of . We proceed to complement this explanation with the image attached below.

Then, the conjugate for is .

2) We proceed to performed all the need algebraic operation until result is found:

1) Given

2) Distributive property

3) Definition of subtraction/

4) Distributive, associative and commutative properties

5) Definition of multiplication//Definition of square root

6) Commutative, associative and distributive properties/

7) Definition of subtraction/Existence of additive inverse

8)

9) Modulative property/Result

3) It is because number and its conjugate have the same numbers but their second components are opposite to each other.

because they could drop even lower..

step-by-step explanation:

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