Hey guys, I need this question in about 2 minutes, please help.

Well I got 9 log 10 (2)/ 3-3log10 (5)

Please correct me if I am wrong

Step-by-step explanation:

You have to apply the rule alogc (b) (b^a)

=

\frac{\log _{10}\left(\frac{\left(\sqrt{8}\right)^4}{\left(\frac{1}{2}\right)^3}\right)}{3-6\log _{10}\left(\sqrt{5}\right)}

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the correct answer is a.) bc< mn 5 stars if this you : )

step-by-step explanation: