Please I could use some help! The population of Kenya was 45.1 million in 2009 and has been growing by 2.3% each year. If this trend continues, in what year will the population exceed 52.2 million?

the year is 2016

Step-by-step explanation:

The computation is shown below:

Given that

The population in 2009 is 45.1 million

And it would be increased 2.3% each year

So,

In the year 2010 it is = 45.1 million × (1 + 0.023) = $46.14 million

In the year 2011, it is = $46.14 million × (1 + 0.023) =$47.20 million

In the year 2012, it is = $47.20 million × (1 + 0.023) = $48.29 million

In the year 2013, it is = $48.29 million × (1 + 0.023) = $49.40 million

In the year 2014, it is = $49.40 million × (1 + 0.023) = $50.54 million

In the year 2015, it is = $50.54 million × (1 + 0.023) = $51.70 million

In the year 2016, it is = $51.70 million × (1 + 0.023) = $52.89 million

Hence, the year is 2016

75

step-by-step explanation:

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.