HELP PLEASE AND FAST IM ON THE BRINK OF DEATH -- Determined to finish her milkshake before Diego, Lin now drinks her 12 ounce milkshake at a rate of 1/3 an ounce per second.

Diego starts with his usual 20 ounce milkshake and drinks at the same rate as before, 2/3 an ounce per second.

1) Graph this situation on
2) What does the graph tell you about the situation and how many solutions there are?

See below.

Step-by-step explanation:

Create a system of equations to represent this scenario.

1) A graph of these equations is attached below. Lin is in red; Diego is in blue.

2) The time (seconds) is on the x-axis, while the milkshake (oz) is on the y-axis. The graph shows the rate of change that the volume of the milkshake is decreasing for both Lin and Diego. The intersection point tells us at what time t (s) Lin and Diego have the same amount of milkshake left.

There is only one solution to this system of equations: (24, 4). This tells us that at t = 24 s, Lin and Diego both have 4 oz of milkshake left.

The zeros, aka where the graph touches the x-axis, tell us at what time Lin and Diego finish their milkshakes.

Lin finishes her milkshake later than Diego, at t = 36 s (36, 0), while Diego finishes his milkshake at t = 30 s (30, 0).

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes