which equation represents a line that passes through the point ( 6,-3 ) and is parallel to the graph of y = 3x + 1

Equation of a line that passes through the point ( 6,-3 ) and is parallel to the graph of y = 3x + 1 is

Step-by-step explanation:

We need to write equation of a line that passes through the point ( 6,-3 ) and is parallel to the graph of y = 3x + 1

The equation will be in slope-intercept form i.e where m is slope and b is y-intercept.

Finding Slope

Since the lines are parallel to each other, their slopes will be equal.

Slope of given line: y = 3x + 1 is 3 (Compare it with general equation we get m = 3)

So, slope of required line is: m=3

Finding y-intercept

Using the point (6,-3) and slope m = 3 we can find y-intercept by using the formula:

So, we get y-intercept: b= -21

Equation of required line

The equation of required line having slope m=3 and y-intercept b = -21 is:

So, equation of a line that passes through the point ( 6,-3 ) and is parallel to the graph of y = 3x + 1 is

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.

step-by-step explanation:

a'(12.5,11.25)

slope=(y1-y2)/(x1-x2)