Plz i need help In triangle ABC, the measure of ∠B is 90°, BC=16, and AC=20. Triangle DEF is similar to triangle ABC, where vertices D, E, and F correspond to vertices A, B, and C, respectively, and each side of triangle DEF is 1/3 the length of the corresponding side of triangle ABC. What is the value of sinF?

Sin F = 0.6

Step-by-step explanation:

From triangle ABC, applying Pythagoras theorem to determine the length AB;

= +

= +

= +

400 = 256 +

= 400 - 256

           = 144

AB =

     = 12

AB = 12, AC = 20, BC = 16

Therefore since ΔABC ≅ ΔDEF, and each side of triangle DEF is the length of the corresponding side of triangle ABC.

Then,

DE = AB =   x 12

     = 4

EF =  BC =   x 16

     =

DF =  AC =   x 20

     =

Then, applying trigonometric function to ΔDEF, we have;

Sin F =

        =

        = 4 ÷

        = 4 x

        =

Sin F = 0.6

im alright what do you need

step-by-step explanation: