2 sides of a triangle have measures of 5 inches and 11 inches which measure could be the length of the third side

the third side must be greater than 6 but less than 16

Step-by-step explanation:

use triangle inequality theorem - 3 scenarios (one of which is discounted because it produces a negative and a side of a triangle cannot be negative)

5 + 11 > 3rd side (n)    n < 16

5 + n > 11       n > 6

11 + n > 5;   n > -6   discounted

ddsf

step-by-step explanation:

dfs

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.