Suppose that 6 out of the 19 doctors in a small hospital are General Practitioners, 9 out of the 19 are under the age of 45, and 3 are both General Practitioners and under the age of 45. What is the probability that you are randomly assigned a General Practitioner or a doctor under the age of 45

12/19

Step-by-step explanation:

We have these events

A = Doctors are general practitioners

B = doctors are under the age of 45

P(A) = 6/19

P(B) = 9/19

P(A n B) = 3/19

Then the probability of being assigned a general practitioner under age 45

P(AuB)

= P(A) + P(B) - P(A n B)

= 6/19 + 9/19 - 3/19

= 12/19

So 12/19 is the probability of getting a general practitioner under age 45.

y > 1/3x

y < = -x + 4

hope this : )