In ΔIJK, \overline{IK} IK
is extended through point K to point L, \text{m}\angle JKL = (5x-3)^{\circ}m∠JKL=(5x−3)
∘
, \text{m}\angle KIJ = (2x+8)^{\circ}m∠KIJ=(2x+8)
∘
, and \text{m}\angle IJK = (x-1)^{\circ}m∠IJK=(x−1)
∘
. Find \text{m}\angle JKL. m∠JKL.

c is the correct answer

step-by-step explanation:

468

step-by-step explanation:

practice. practice. practice.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.