The sum of the perimeters of 2 different squares is 68 feet, and the difference between their perimeters is 12 feet. What is the side length of each square?

9514 1404 393

Step-by-step explanation:

The side lengths are 1/4 of the perimeter, so we can say ...

  the sum of side lengths is 68 ft/4 = 17 ft

  the difference of side lengths is 12 ft/4 = 3 ft

Using x to represent the side length of the smaller square, we have ...

  x + (x +3) = 17 . . . . . . the larger square has side length x+3

  2x = 14 . . . . . . . . . subtract 3

  x = 7 . . . . . . . . divide by 2

The side lengths of the squares are 7 feet and 10 feet.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!