A student has started a lawn care business in the summer. He charges $21 per hour
to mow lawns and $17 per hour for
gardening. Because he has other
obligations, he can only work for at most
16 hours per week. His goal is to make at
least $275 per week.
Write a system of linear inequalities to
model this situation. Use M for hours
spent mowing lawns and G for hours
spent gardening

Step-by-step explanation:

$21=per hour mowling

$17=per hour gardening

only work 16 hours per week

Goals =$275 per week

$275÷16 hours=$17.1875(Each hour in a week)

mow lawns= $17.1875 ×$12=$206.25(for 16 hours)

gardening=$17.1875 ×$17=$292.1875(for 16 hours)

mowling lawns=$275÷$21=13.0952380952(13 hours,12 minutes and 30 seconds)

Gardening =$275÷$17= $16.1764705882 (970 hours,9 minutes,80 seconds)

A little help not fully answered

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240