an equation of a line that passes through the point (15,2) and is perpendicular to the line -10x+8y = 3?

Step-by-step explanation:

Changing to slope-intercept form:

-10x + 8y = 3         {add 10x to both sides}

8y = 10x + 3         {divide both sides by 8}

y = ⁵/₄x + ³/₈

Two lines are perpendicular if the product of their slopes is equal -1:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

y = ⁵/₄x + ³/₈   ⇒   m₁=⁵/₄

⁵/₄×m₂ = -1        ⇒    m₂ = -⁴/₅

The line y=-⁴/₅x+b passes through point (15, 2) so the equation:

2 = -⁴/₅×15 + b must be true

2 = -12 + b

b = 14

Therefore equation in  slope-intercept form:

                                                     y = -⁴/₅x + 14

whatever you can spend with $11.53 or under.

step-by-step explanation:

20 - 8.47 = 11.53. take away the money he used for lunch from the starting amount of 20.

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation: