Find the size of the final unknown interior angle in a polygon whose other interior angles are: 162°, 115°, 125°, 138°, 105° and 98°.

Step-by-step explanation:(2ñ-4)90

(7×2-4)90

=900°

900-(162+125+148+105+98+115)

900-753

=147°

Step-by-step explanation:

Sum of interior angle for a polygon = (n-2)180

It has 6 sides

=(6-2)180

=4*180

=720

Therefore, let the unknown interior angle =x

x+162+115+120+148+85=720

x+630=720

x=720-630

x=90^

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step-by-step explanation:

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.