The base of a traingular field is twice its altitude , If the cost of levelling the field , at the rate of rupess 10 per m2 is rupees 4,000 , find it base and altitude

Base=40m and

Altitudes=20m

Step-by-step explanation:

Area of the field can be calculated as

Area= total cost / rate

Where total cost= 4,000 rupees

Rate= 10 per m2

Area of the field= 4000/10

= 400m^2

Let the altitudes be denoted as "x metre"

Then the base = 2x

Area= 1/2bh

Where b= base

h= altitudes

Then if we substitute we have

400m^2= 1/2× x × 2x

400= x^2

x= √400

x=20m

Then altitudes = 20m

the base = 2x= 2×20=40m

Hence, it base and altitude are 40m and 20m respectively.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!