A triangle has A, B, and C located at(-3, 0). (3, 0), and (0, 4), respectively, on the coordinate plane. The medians of (triangle)ABC intersect at the point with which coordinates? Round each coordinate to the nearest tenth if necessary.

A. (1.5, 2)

B. (-1.5, 2)

C. (0, 1.3)

D. (0, 0)

Given:

Vertices of a triangle ABC are A(-3,0), B(3,0) and C(0,4).

To find:

The intersection point of all the medians of the triangle ABC.

Solution:

We know that, intersection point of all the medians of a triangle is called centroid.

The formula of centroid is

Vertices of a triangle ABC are A(-3,0), B(3,0) and C(0,4).

Round each coordinate to the nearest tenth.

The coordinates of required point are (0,1.3). Therefore, the correct option is C.

597

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!