Can someone help me please

Explanation:

This is a 45-45-90 right triangle. Any triangle of this form is isosceles, where the two legs are the same length. In this case, m and n are those two legs. So m = n.

We can then apply the Pythagorean theorem to say

a^2 + b^2 = c^2

m^2 + n^2 = (9*sqrt(2))^2

m^2 + m^2 = 9^2*(sqrt(2))^2

2m^2 = 81*2

m^2 = (81*2)/2

m^2 = 81

m = sqrt(81)

m = 9

As a shortcut, the hypotenuse of a 45-45-90 triangle is equal to sqrt(2) times the length of either leg. If m is the length of the leg, then m*sqrt(2) is the length of the hypotenuse. So in a sense, we take this thought process backwards to go from a hypotenuse 9*sqrt(2) to a leg length of 9.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !