For the school play, the advance tickets cost 3, while tickets at the door cost 5. Thirty more tickets were sold at door than in advance, and was collected. How many of each kind of ticket were sold? Write your answer in a sentence.

Number of tickets sold in advance = 310

Number of tickets sold  at the door = 340

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

For the school play, the advance tickets cost $3, while tickets at the door cost $5. Thirty more tickets were sold at the door than in advance, and $2630 was collected. How many of each kind of ticket were sold?

The explation of the answer is now given as follows:

Let a represents number of tickets sold in advance. Therefore, we have:

a = number of tickets sold in advance at $3 each

a + 30 = number of tickets sold  at the door at $5 each

The total amount collected can be represented by this equation:

3a + 5(a + 30) = 2630

Solving for a, wee have:

3a + 5a + 150 = 2630

8a = 2630 - 150

8a = 2,480

a = 2,480 / 8

a = 310

Therefore, this implies:

Number of tickets sold in advance = 310

Number of tickets sold  at the door = a + 30 = 310 + 30 = 340

i used to know how to do this in 7th but i forget easily

step-by-step explanation: