Willie and anjali each improved their yards by planting daylilies and ivy. They bought their supplies from the same store. Willie spent $116 on 12 daylilies and 4 pots of ivy. Anjali spent $60 on 6 daylilies and 3 pots of ivy. Find the cost of one daylily and the cost of one pot of ivy

the cost of one day lily = $9 and cost of one pot of ivy = $2

Step-by-step explanation:

Step 1

let day lilies be rep as d

and ivy be represented as i

So that The expression for what Willie spent on  12 day lilies and 4 pots of ivy = $116 be

12 d+ 4i = 116 equation 1

and for Anjali spending  $60 on 6 day lilies and 3 pots of ivy be

6d+ 3i = $60 equation 2

Step 2 --- Solving

 12 d+ 4i = 116 equation 1

6d+ 3i = $60 equation 2

Multiply equation 2 by (2) and subtracting equation 1  from it

12d+ 6i= 120

--12 d+ 4i = 116

2 i= 4

i = 4/2 = 2

TO find d, putting the value of i = 2 in equation 1 and solving

12d+ 4(2) = 116

12d= 116-8

12d= 108

d= 108/12= 9

Therefore the cost of one day lily = $9 and cost of one pot of ivy = $2

step-by-step explanation:

if x = 2 you have to find x to finish the problem

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option