1) 22 Kg + 34 kg = 2) 94 L + 28 L =

3) 46 cm + 56 mm =

4) 98 cm + 45 m =

5) 234 g + 29 Kg =
6) 40 Km + 35 mm =

7) 89 KL + 56 L =

8) 783 km + 354 km =

9) 95 L + 456 cL =

10) 45 cm + 78 m =
11) 19 1/7 mm + 65 2/3 mm =

12) 77 km 8/3 m + 41 km 15 m =

13) 56 kL 4/5L + 98 KL 1/5 L =

14) 46 kg 77g + 71 kg =

15) 34 m 3/7 cm + 231m 3/5 cm =

16) 782 L 56 mL + 67 L 2/9mL =

17) 35 km 1/7 cm + 78 Km 2/8 cm =

18) 208 kL 65 mL + 51 kL 72 mL =

19) 635 cm + 89 cm =

20) 524 kg 12 cg + 34 kg 3/8 cg =

1) 22 Kg + 34 kg = 56 kg

2) 94 L + 28 L = 122 L

3) 46 cm + 56 mm = (46×10) + 56 = 516 mm

4) 98 cm + 45 m = 98 + (45×100) = 4,598 cm

5) 234 g + 29 Kg = 234 + (29×1000) = 29,234 Kg

6) 40 Km + 35 mm = (40×1,000,000) + 35 = 40,000,035 mm

7) 89 KL + 56 L = (89×1000) + 56 = 89,056 L

8) 783 km + 354 km = 1,137 km

9) 95 L + 456 cL = (95×100) + 456 = 9,956 cL

10) 45 cm + 78 m = 45 + (78×100) = 7,846 cm

11) 19 1/7 mm + 65 2/3 mm = 84 17/21 mm

12) 77 km 8/3 m + 41 km 15 m = 118 km 53/3 m

13) 56 kL 4/5L + 98 KL 1/5 L = 154 KL 1 L

14) 46 kg 77g + 71 kg = 117 kg 77 g

15) 34 m 3/7 cm + 231m 3/5 cm = 265 m 36/35 cm

16) 782 L 56 mL + 67 L 2/9mL = 849 L 506/9 mL

17) 35 km 1/7 cm + 78 Km 2/8 cm = 113 km 11/28 cm

18) 208 kL 65 mL + 51 kL 72 mL = 259 kL 137 mL

19) 635 cm + 89 cm = 724 cm

20) 524 kg 12 cg + 34 kg 3/8 cg = 558 kg 99/8 cg

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

(a) the volume of the cone is 20/3 in3

hence, option a is correct.