Factor the trinomial:
-3y^2 + 7y + 20

here you goes hope it helps you

Step-by-step explanation:

1

Common factor

−

3

2

+

7

+

2

0

-3y^{2}+7y+20

−3y2+7y+20

−

1

(

3

2

−

7

−

2

0

)

-1(3y^{2}-7y-20)

−1(3y2−7y−20)

2

Use the sum-product pattern

−

1

(

3

2

−

7

−

2

0

)

-1(3y^{2}{\color{#c92786}{-7y}}-20)

−1(3y2−7y−20)

−

1

(

3

2

+

5

−

1

2

−

2

0

)

-1(3y^{2}+{\color{#c92786}{5y}}{\color{#c92786}{-12y}}-20)

−1(3y2+5y−12y−20)

3

Common factor from the two pairs

−

1

(

3

2

+

5

−

1

2

−

2

0

)

-1(3y^{2}+5y-12y-20)

−1(3y2+5y−12y−20)

−

1

(

(

3

+

5

)

−

4

(

3

+

5

)

)

-1(y(3y+5)-4(3y+5))

−1(y(3y+5)−4(3y+5))

4

Rewrite in factored form

Solution

−

1

(

−

4

)

(

3

+

5

)

a = 3.14

b = 18

c = 18/5 or 3.6 or 3 3/5

step-by-step explanation: