A line passes to the point (4,6) and has a slope of -3/4. Which is the equation of the line

Step-by-step explanation:

use point-slope formula [ y- y1 = m(x - x1) ]  with the point you are given as point 1 (x1,y1) = (4,-6) and the slope m that you are also given m = -3/4

y-y1 = m(x -x1)

y-(-6) = -3/4(x -4)

y + 6 = -3/4(x-4)

you can work this toward the slope-intercept formula of y = mx +b by doing the following

y + 6 = -3/4x +3    (distribute the -3/4)

y = -3/4x + 3 -6   ( move the 6 to the other side )

y = -3/4x - 3  

there  you go  :) choice 1 looks good if you're still able to put in the answer