Two siblings are racing. The older sibling can run at a constant speed of 11 feet per second. The younger sibling can run at a constant speed of 7 feet per second. If the younger sibling is given a 32-foot head start in the race, how long will it take the older sibling to catch the younger sibling, and how far will the older sibling have run at that moment

i'm sure goog can you get that answer

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!