if thrice my age 6 years ago be subtracted from twice my present age the result is present age then my present age is what

9 years

Step-by-step explanation:

Let the present age = x

Age 6 years ago = x - 6

Thrice my age 6 years ago = 3*(x -6) =3x - 3*6 = 3x - 18

Twice my present age = 2 *x = 2x

Thrice my age 6 years ago be subtracted from

twice my present age  = 2x -  (3x - 18)

2x - (3x - 18) = x

2x - 3x  + 18 = x                  

    -x  + 18 = x              {Add x to both sides}

             18 = x + x

              18 = 2x              {Divide both sides by 2}

           18/2 = x

x = 9 years

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204