Question 4 (1 point) A ball is thrown from a mountain 960 feet high, into the air with an upward velocity of 64 ft/s. When did the ball hit the

ground? And What was the max height it reached?

The ball will hit the ground at 10 seconds and its maximum height is 1024 feet.

Step-by-step explanation:

Height of a mountain, h = 90 feet

Upward velocity of a ball, u = 64 ft/s

Its height as a function of time can be written by using the second equation of motion as follows :

.....(1)

When it will hit the ground, f(x) = 0

It is quadratic equation.

t = -6 s and t = 10 s

Neglecting -6 seconds, the ball will hit the ground at 10 seconds.

For maximum height,

Put f'(x) = 0

Put t = 2 in equation (1)

Hence, the ball will hit the ground at 10 seconds and its maximum height is 1024 feet.

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation: