Can someone answer these two questions I submitted a photo of them it’s worth 50 points

Step-by-step explanation:

1). Let the equation of the line is,

  y = mx + b

  Here, m = slope of the line

  b = y-intercept

  Slope of a line passing through two points,

  m =

  We take two points from the table given (-3, -19) and (0, -1)

  m =

  m = 6

  y - intercept 'b' = -1 [For x = 0]

  Therefore, equation of the line will be,

  y = 6x - 1

2). Equation of a line passing through a point (x', y') is,

   y - y' = m(x - x')

   Slope of the line passing through two points and is,

   m =

   We take two points from the given table as (2, 12) and (3, 18).

   Slope of the line passing through these points will be

   m = = 6

   Equation of the line passing through (2, 12) will be,

   y - 12 = 6(x - 2)

   y = 6x - 12 + 12

   y = 6x

By using a graphing tool we can graph these lines representing the tables.    

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4

3

step-by-step explanation:

because where the point where the 2 lines intersect is (3,-1) the x value is 3