The ratio of Val's savings to Dan is 2:3 at first. After Dan spent P3000.00, Val's saving became 11/3 more of that Dan's remaining savings. What is the total amount of saving the two had at first

The total amount of saving the two had at first is P7500 and this can be determined by using the arithmetic operations and given data.

Given :

Given that the ratio of Val's savings to Dan is 2:3 at first. Now, assume that the total amount of savings they had at first was x. So:

Val's had - 2x/5

Dan's had - 3x/5

Now, it is also given that Dan's spent P3000. So, the amount left is:

It is given that Val's saving became 4/3 more of that Dan's remaining savings. That is:

x = P.7500

The total amount of saving the two had at first is P7500.

For more information, refer to the link given below:

link

P.7500.00

Step-by-step explanation:

We are told that:

The ratio of Val's savings to Dan is 2:3 at first.

Now, Dan spent P3000.00 and Val's saving became 1⅓ more of that Dan's remaining savings.

Let's say the total amount of savings they had at first was x.

Thus;

Val had: 2x/5

Dan had: 3x/5

Now, Dan spent P3000.00.

So amount Dan has left = (3x/5) - 3000

We are told Val's savings is now 1⅓ = 4/3 times that of Dan's remaining savings

Thus; 2x/5 = (4/3)((3x/5) - 3000)

2x/5 = 12x/15 - 4000

Multiply through by 15 to get;

6x = 12x - (3000 × 15)

6x = 12x - 45000

Rearranging, we have;

12x - 6x = 45000

6x = 45000

x = 45000/6

x = P.7500

what graph

step-by-step explanation: