A right triangle has base 130m. solve the rest of the triangle

Step-by-step explanation:

Sides: a = 130   b = 183.848   c = 130

Area: T = 8450

Perimeter: p = 443.848

Semiperimeter: s = 221.924

Angle ∠ A = α = 45° = 0.785 rad

Angle ∠ B = β = 90° = 1.571 rad

Angle ∠ C = γ = 45° = 0.785 rad

Height: ha = 130

Height: hb = 91.924

Height: hc = 130

Median: ma = 145.344

Median: mb = 91.924

Median: mc = 145.344

Inradius: r = 38.076

Circumradius: R = 91.924

Vertex coordinates: A[130; 0] B[0; 0] C[-0; 130]

Centroid: CG[43.333; 43.333]

Coordinates of the circumscribed circle: U[65; 65]

Coordinates of the inscribed circle: I[38.076; 38.076]

Exterior (or external, outer) angles of the triangle:

∠ A' = α' = 135° = 0.785 rad

∠ B' = β' = 90° = 1.571 rad

∠ C' = γ' = 135° = 0.785 rad

18.36. give me brainliest!

step-by-step explanation:

you have to multiply 1.53 by 12 so the equation is 12x1.53 and then that is your answer.

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )