Write a real-world problem where you would want to compare rates of change for two different functions.

Answer and Step-by-step explanation:

Let us assume two boys are jogging.

Boy 1 jogging speed is 10 kilometres per hour

Boy 2 jogging speed is 20 kilometres per hour

This can be represented in terms of distance, d and time, t. When we do this, we have:

d = 10t boy 1

d = 20t boy 2

This implies that boy 1 rate of change is 10 kilometers for every one hour and boy 2 is 20 kilometers for every 1 hour.

From here, we can conclude that the rate of change of boy 2 is twice the rate of change of boy 1.

what

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: