Una maquina que fabrica tornillos produce un 3% de piezas defectuosas. Si hoy se han apartado 51 tornillos defectuosos cuantos tornillos ha fabricado la maquina?

1700 tornillos

Step-by-step explanation:

Dado que la máquina produce un 3% de tornillos defectuosos en un día. Produjo 51 tornillos defectuosos en un día.

Deje que el número total de tornillos producidos ese día sea x

Por lo tanto;

3% de x = 51

3/100 * x = 51

x = 51 * 100/3

x = 1700 tornillos

, and

for

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote , , , so that we can call

note the following:

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from , to get to , we add

from , to get to , we add

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

, and for

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).