Find the maximum value of P = x + 6y
subject to the following constraints:
(2x + 4y < 10
X + 9y < 12
x > 0
y0
P = [?]

(3, 1)

Step-by-step explanation:

Given the following constraints:

2x + 4y ≤ 10

x + 9y ≤ 12

x ≥ 0

y ≥ 0

We have to first graph the above constraints and secondly, we find the  boundary points for the feasible region. This is done by plotting the graphs of 2x + 4y ≤ 10  and x + 9y ≤ 12.

 From the graph, the following points satisfy the constraints:

(0,0) , (3,1) , (0,4/3) , (5,0)

Given that:

P = x + 6y

For (0, 0): P = x + 6y = 0 + 6(0) = 0

For (3, 1): P = x + 6y = 3 + 6(1) = 9

For (0, 4/3) P = x + 6y = 0 + 6(4/3) = 8

For (5, 0) P = x + 6y = 5 + 6(0) = 5

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

the radius is 2 times the diameter.

step-by-step explanation: