Suppose that Cecil, the tightrope walker, can only travel lengths of 5 feet, 6 feet, and 8 feet. • He can travel forward (positive 5, 6, 8)
• backward negative (-5, -6-8)
can go past the ladder and come back.
.
Show TWO number expressions that will represent a way for Cecil to cross a tightrope of
12 feet. ONE way MUST use a negative.
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The two expressions are;

1) -8 ft. + 3 × 6 ft. = 12 feet

2) -6 ft. + 2 × 5 ft. + 8 ft. = 12 feet

Step-by-step explanation:

The given parameters are;

The lengths in feet Cecil can travel = 5 feet, 6 feet, and 8 feet

The distances Cecil can travel forward = (positive 5, 6, 8)

Backwards Cecil can travel distances of (-5, -6, -8)

Cecil can go forward past the ladder and return back

Therefore, the number expressions by which Cecil can cross a tightrope 12 feet long are;

1) -8 ft. + 3 × 6 ft. = 12 feet

Which is to go back 8 feet and then to go forward 6 feet three times

2) -6 ft. + 2 × 5 ft. + 8 ft. = 12 feet

Which is to go back 6 feet then to go forward in 5 feet two times and then in forward again in 8 feet.

ab will be equal to