A line is perpendicular to y = -x + 1 and intersects the point (-5,1).
What is the equation of this
perpendicular line?

y = 5x + 26

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - x + 1 ← is in slope- intercept form

with slope m = -

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = 5 , thus

y = 5x + c ← is the partial equation

To find c substitute (- 5, 1) into the partial equation

1 = - 25 + c ⇒ c = 1 + 25 = 26

y = 5x + 26 ← equation of perpendicular line

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204