Choose the correct answer. Distance between Train 1 and Train 2 =95 miles.
Average speed of Train 1 = 45 mph.
Average speed of Train 2 60 mph.
If both trains leave at the same time and travel toward each other but on parallel tracks, in how much time will their
engines be opposite each other? (Hint: When the engines are opposite each other, together the trains will have traveled
95 miles. Their relative speed of travel is the sum of their respective speeds, or 105 mph.)
Travel time = Mhours

Step-by-step explanation:

Distance between Train 1 and Train 2=95 miles

Avg speed Train 1 = 45mph, avg speed Train 2=60mph

If both trains leave at the same time and travel toward each other but on parallel tracks, in how much time will their engines be opposite each other?

:

Let t = travel time (in hrs) until they are opposite each other

:

Like the hint said, when this happens the total distance traveled by both trains will be 95 mi.

:

write a distance equation from this fact: Dist = speed * time

;

Train 1 dist + train 2 dist = 95 mi

45t + 60t = 95

:

105t = 95

t = 95%2F105

t = .90476 hrs

or

.90476 * 60 = 54.3 min

:

:

Check solution by finding the total of the distances the two train travel

45(.90476) + 60(.90476) =

40.7 + 54.3 = 95 mi

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.