If the expected value (the mean) of successes in a binomial experiment of 100 trials is 55. Which of the following are not true?Let x = the no. of successes of the 100 trials. Then P(s) = p = 55/100 = 0.55The standard deviation of the binomial distribution is approximately σ = √(npq) = √(100x0.55x0.45) ≈ 4.97The probability distribution of x = B(100, 0.55) can be approximated by N(55, 4.97)a) I onlyb) II onlyc) I and IId) All of the statements are true

All of the statements are true

Step-by-step explanation:

Given that :

Number of trials (n) = 100

Expected number of successes = 55

The number of successes of the 100 trials :

Number of successes / number of trials = 55 / 100 = expected number of successes / n = 55/ 100 = 0.55

Using Normal approximation :

Standard deviation (σ) = √(npq) ; q = 1 - p = 1 - 0.55 = 0.45

σ = √(100 * 0.55 * 0.45) = √24.75 = 4.975

The probability distribution of x = B(n, p) = x = B(100, 0.55)

Using approximation ; N(p, σ) = N(55, 4.97)

Hence, All of the statements are true

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

27 + 13x + 15 = (x + 5)( =

step-by-step explanation:

27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( = 27 + 13x + 15 = (x + 5)( =