For what value of “x” is the figure the given special parallelogram?

x = 6

Step-by-step explanation:

(In reference to my diagram.... my diagram is similar to the diagram in the question)

We know that diagonals of a square bisect each other at right angles.

In ΔBOC ,

•OB = OC (Diagonals of square bisect each other)

=> ∠OBC = ∠OCB = (7x + 3)°        (∵ OB = OC)

• ∠BOC = 90° (Diagonals intersect at right angles)

Using angle sum property of triangle ,

∠OBC + ∠OCB + ∠BOC = 90°

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )