Zoe is using the figure shown below to prove Pythagorean Theorem using triangle similarity: In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC.

Which of these could be a step to prove that BC2 = AB2 + AC2?
1) by distribution, AC2 plus AB2 = BC multiplied by The quantity DC plus AB
2) by distribution AC2 plus AB2 = BC multiplied by the quantity DC plus BD
3) by distribution AC2 plus AD2 = BC multiplied by the quantity DC plus AB
4) by distribution AC2 plus AD2 = BC multiplied by the quantity DC plus BD

huh? im pretty sure it is in 199

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).